RIDDLE 41 -- Answer
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AnAspiringSoul
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ANSWER:
The boy gave 20 chocolates the second time.
In the beginning the boy and the girl were having 90 and 30 each. Now they are having 60 each.
Explanation:
Let the girl have x
And the boy y.
The boy was initially having thrice that of the girl.
So, y = 3x
Then he gives 10 to her.
So, the girl has x+10 and
the boy has y-10 = 3x-10
Then, he was having twice as that of her.
So, y-10 = 3x-10= 2(x+10)
3x-10= 2x + 20
3x - 2x = 20 + 10
x = 30
and y = 3x = 90
So, the girl and the boy initially had 30 & 90.
After giving 10, the boy had 80 and the girl 40.
This is twice as that of the girl.
So, the boy gives 20.
Now, both of them have 60 each.
Got it...
Is that clear?
Am I correct?
Shall we proceed?
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